3x^2+5x-2=98

Solution for 3x^2+5x-2=98 equation:

3x^2+5x-2=98

We move all terms to the left:

3x^2+5x-2-(98)=0

We add all the numbers together, and all the variables

3x^2+5x-100=0

a = 3; b = 5; c = -100;
Δ = b2-4ac
Δ = 52-4·3·(-100)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-35}{2*3}=\frac{-40}{6}
=-6+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+35}{2*3}=\frac{30}{6}
=5
$